DCP-558: The kth Difference Back to All Problems

Beginner Math > Basic Math

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The **kth group of Odd numbers** contains exactly **k consecutive odd** numbers. Such as, 1st group of odd numbers contains only one number, 1; the 2nd group of odd numbers contains two numbers, 3 and 5 and so on. Similarly, the **kth group of Even numbers** contains exactly **k consecutive even** numbers. Such as, 1st group of even numbers contains only one number, 2; the 2nd group of even numbers contains two numbers, 4 and 6 and so on. It is guaranteed that, the numbers are consecutive so that **there is no number that stays in different two groups**. Now, you have the easiest task to do in your life. :-P Given the value of **k**, calculate the difference of the sum of **kth group of Even numbers** and **kth group of Odd numbers**. Input: ------ Inputs starts with **T** (**1 ≤ T ≤ 1000**), denoting the total number of testcases. Next each **T** lines there will be a number, **k** (**1 ≤ k ≤ 10^18**). Output: ------- Output the desired value as mentioned in the problem statement. Sample Input ------------ 1 4 Sample Output ------------- 4 Explanation: ------------- For k = 4, we have the even group, {14,16,18,20}, sum of them is, 14+16+18+20 = 68 and the odd group, {13,15,17,19}, sum of them is, 13+15+17+19 = 64. Now the difference is, 68-64 = 4. :)

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Problem Setter:

Shah Newaj Rabbi Shishir

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