# DCP-316: Names Back to All Problems

Easy Math > Counting

We know that **Mr. Royel** is the oldest man and his family is the biggest family in the world. So, he faces a problem to find names for new family member. That's why he comes to you, and you have to help him. You are given the length of names **L** and a string **S**. You have to find the number of distinct names which have the string **S** as a **suffix**. The all the letters in the name should contain ***lowercase English alphabets***. **Note: Suffix is an affix occurring at the end of a word, base, or phrase.** Input: -- Input start with test cases **T**. Each test case there is one integer **L** , length of names and a string **S**. Name and string will contain only lowercase letter **‘a’-’z**’. Constrains: -- 1<=T<=10000 1<=L<=100 1<=|S| <= L L-|S|<=10 Output: -- Each case print a single line the total number of names.See the explanation section below for more clarity. Sample Input: -- 3 2 ab 3 ab 4 ab Sample Output -- 1 26 676 **Explanation:** **First case**: There is only one possible name "ab". **Second case**: There is 26 combinations possible, like "aab", "bab", "cab", "dab", "eab", "fab", "gab", "hab", "iab", "jab", "kab", "lab", "mab", "nab", "oab", "pab", "qab", "rab", "sab", "tab", "uab", "vab", "wab", "xab", "yab" & "zab". Every names have "ab" as a suffix and length is 3. **Third case**: Out of 4 place , 2 place are occupied with string "ab". So, there are only 2 places to change and on every place we can place 26 different characters. So total: 26*26=676 ways.

### Problem Limits

 Language Time Limit (seconds) C 1.00 C++ 1.00 C++14 1.00 C# 1.50 Go 1.50 Java 1.50 JavaScript 1.50 Objective-C 1.50 Perl 1.50 PHP 1.50 Python 1.50 Python3 1.50 Ruby 1.50 VB.Net 1.50

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